![]() Use this length (and the fact that Pt has a face-centered unit cell) to calculate the density of platinum metal in kg/m 3 (Hint: you will need the atomic mass of platinum and Avogadro's number). Problem #12: The unit cell of platinum has a length of 392.0 pm along each side. What is the atomic radius of platinum? (1 Å = 10 -8 cm.) Problem #11: Platinum has a density of 21.45 g/cm 3 and a unit cell side length 'd' of 3.93 Ångstroms. Use these data to calculate a value for Avogadro's Number. Problem #10: Iridium has a face centered cubic unit cell with an edge length of 383.3 pm. What is the center-to-center distance between nearest silver atoms? Problem #9: Metallic silver crystallizes in a face-centered cubic lattice with L as the length of one edge of the unit cube. Problem #8: The density of an unknown metal is 2.64 g/cm 3 and its atomic radius is 0.215 nm. The density of the element is 1.54 g/cm 3. Problem #7: A metal crystallizes in a face-centered cubic lattice. Find the gram-atomic weight of this metal and tentatively identify it. An X-ray diffraction experiment measures the edge of the face-centered cubic unit cell as 4.06 x 10 -10 m. You find the density of the metal to be 11.5 g/cm 3. Problem #6: You are given a small bar of an unknown metal. (a) What is the density of solid krypton? (b) What is the atomic radius of krypton? (c) What is the volume of one krypton atom? ![]() Problem #5: Krypton crystallizes with a face-centered cubic unit cell of edge 559 pm. Assuming that calcium has an atomic radius of 197 pm, calculate the density of solid calcium. Problem #4: Calcium has a cubic closest packed structure as a solid. Problem #3: Nickel has a face-centered cubic structure with an edge length of 352.4 picometers. If the density of the metal is 8.908 g/cm 3, what is the unit cell edge length in pm? ![]() Problem #2: Nickel crystallizes in a face-centered cubic lattice. Calculate the atomic radius of palladium. Problem #1: Palladium crystallizes in a face-centered cubic unit cell. Finally, I will explain how systems with J eff = 1/2 moments on the fcc lattice can host exotic states of matter.Face-centered cubic problem list Face-centered cubic problem list ![]() Therefore, I will also discuss the possibility of realizing significant Kitaev interactions in these families and their impact on the collective magnetic properties. Notably, both structure types consist of a magnetic face-centered-cubic (fcc) sublattice, where nearest neighbor Kitaev interactions are symmetry-allowed through extended superexchange pathways. One or both conditions are realized in the double perovskite iridate and iridium halide families, which have the general chemical formulas A 2BIrO 6 and A 2IrX 6 respectively. In this talk, I will discuss how spacing the iridium ions further apart and incorporating anions with low electronegativities into the crystal structure are useful design criteria for achieving unprecedented proximity to the ideal J eff = 1/2 limit. Of particular interest are systems with octahedrally-coordinated magnetic ions in a 5d 5 electronic configuration, as the combination of large cubic crystal fields and strong spin-orbit coupling is expected to generate a J eff = 1/2 electronic ground state that may be an essential ingredient for new classes of quantum spin liquids and superconductors. Heavy transition metal magnets have been intensely investigated over the last decade due to their penchant for hosting a wide variety of exotic phases and phenomena. ![]()
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